Given that the volume of a metal sphere is 38 | vedclass

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(A) The volume of a sphere is given by the formula $V = \frac{4}{3} \pi r^{3}$.Given $V = 38808 \, cm^{3}$.$\frac{4}{3} 	imes \frac{22}{7} 	imes r^{

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$21 \, cm$ and $5544 \, cm^{2}$

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(A) The volume of a sphere is given by the formula $V = \frac{4}{3} \pi r^{3}$.Given $V = 38808 \, cm^{3}$.$\frac{4}{3} 	imes \frac{22}{7} 	imes r^{3} = 38808$.$r^{3} = 38808 	imes \frac{3 	imes 7}{4 	imes 22} = 9261$.Taking the cube root,$r = \sqrt[3]{9261} = 21 \, cm$.The surface area of a sphere is given by $A = 4 \pi r^{2}$.$A = 4 	imes \frac{22}{7} 	imes 21 	imes 21 = 4 	imes 22 	imes 3 	imes 21 = 5544 \, cm^{2}$.Thus,the radius is $21 \, cm$ and the surface area is $5544 \, cm^{2}$.

Given that the volume of a metal sphere is $38808 \, cm^{3}$. Then,its radius and its surface area are?

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