Given the linear equation $2x + 3y - 8 = 0$,write another linear equation in two variables such that the geometrical representation of the pair so formed is parallel lines.

(A) For two lines $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$ to be parallel,the condition is $\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}$.
Given the equation $2x + 3y - 8 = 0$,we have $a_1 = 2, b_1 = 3, c_1 = -8$.
To satisfy the condition,we can choose $a_2 = 4$ and $b_2 = 6$ (which makes $\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{1}{2}$) and choose $c_2$ such that $\frac{c_1}{c_2} \neq \frac{1}{2}$.
Let $c_2 = -10$. Then the equation is $4x + 6y - 10 = 0$.
Checking the condition: $\frac{2}{4} = \frac{3}{6} \neq \frac{-8}{-10}$,which simplifies to $\frac{1}{2} = \frac{1}{2} \neq \frac{4}{5}$.
Thus,$4x + 6y - 10 = 0$ is a valid answer.