Two straight paths are represented by the equ | vedclass

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(B) The given linear equations are:$x-3y-2=0$ ..... $(i)$$-2x+6y-5=0$ ..... $(ii)$Comparing these equations with the general form $ax+by+c=0$,we get:F

Vedclass · Accepted Answer

No,they do not cross each other.

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(B) The given linear equations are:$x-3y-2=0$ ..... $(i)$$-2x+6y-5=0$ ..... $(ii)$Comparing these equations with the general form $ax+by+c=0$,we get:For equation $(i)$: $a_1=1, b_1=-3, c_1=-2$For equation $(ii)$: $a_2=-2, b_2=6, c_2=-5$Now,calculating the ratios:$\frac{a_1}{a_2} = \frac{1}{-2} = -\frac{1}{2}$$\frac{b_1}{b_2} = \frac{-3}{6} = -\frac{1}{2}$$\frac{c_1}{c_2} = \frac{-2}{-5} = \frac{2}{5}$Since $\frac{a_1}{a_2} = \frac{b_1}{b_2} 
eq \frac{c_1}{c_2}$,the lines are parallel.Therefore,the two straight paths represented by the given equations never cross each other.

Two straight paths are represented by the equations $x-3y=2$ and $-2x+6y=5$. Check whether the paths cross each other or not.

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