Given the lines y + 2x = 3 and y + 2x = 5 cut | vedclass

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(B) The lines are $L_1: 2x + y - 3 = 0$ and $L_2: 2x + y - 5 = 0$. These are parallel lines. For $L_1$,the intercepts are $x = 1.5$ $(A)$ and $y = 3$

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Statement-$1$ is false,Statement-$2$ is true

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(B) The lines are $L_1: 2x + y - 3 = 0$ and $L_2: 2x + y - 5 = 0$. These are parallel lines. For $L_1$,the intercepts are $x = 1.5$ $(A)$ and $y = 3$ $(B)$. For $L_2$,the intercepts are $x = 2.5$ $(C)$ and $y = 5$ $(D)$. The region between the lines is given by $3 For the point $(2, 3)$,we calculate $2(2) + 3 = 4 + 3 = 7$. Since $7 > 5$,the point $(2, 3)$ does not lie between the lines. Therefore,Statement-$1$ is false. Statement-$2$ is also false because the point does not lie between the lines.

Given the lines $y + 2x = 3$ and $y + 2x = 5$ cut the axes at $A, B$ and $C, D$ respectively.
Statement-$1$ : $ABDC$ forms a quadrilateral and the point $(2, 3)$ lies inside the quadrilateral.
Statement-$2$ : The point $(2, 3)$ lies between the two parallel lines.

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Given the lines $y + 2x = 3$ and $y + 2x = 5$ cut the axes at $A, B$ and $C, D$ respectively. Statement-$1$ : $ABDC$ forms a quadrilateral and the point $(2, 3)$ lies inside the quadrilateral.Statement-$2$ : The point $(2, 3)$ lies between the two parallel lines.