Glucose and gluconic acid on oxidation with d | vedclass

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Question

(C) Glucose $(CHO-(CHOH)_4-CH_2OH)$ and gluconic acid $(COOH-(CHOH)_4-CH_2OH)$ both undergo oxidation with dilute $HNO_3$ to form saccharic acid $(COO

Vedclass · Accepted Answer

one primary alcoholic group

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(C) Glucose $(CHO-(CHOH)_4-CH_2OH)$ and gluconic acid $(COOH-(CHOH)_4-CH_2OH)$ both undergo oxidation with dilute $HNO_3$ to form saccharic acid $(COOH-(CHOH)_4-COOH)$.In this reaction,the terminal primary alcoholic group $(-CH_2OH)$ is oxidized to a carboxylic acid group $(-COOH)$.Since only one $-CH_2OH$ group is present in the glucose molecule and it gets converted to $-COOH$,this reaction confirms the presence of one primary alcoholic group in glucose.

Glucose and gluconic acid on oxidation with dilute nitric acid $(HNO_3)$ form saccharic acid. This reaction confirms that glucose contains:

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