Half-life of a radioactive substance $A$ is two times the half-life of another radioactive substance $B$. Initially, the number of nuclei of $A$ and $B$ are $N_A$ and $N_B$ respectively. After three half-lives of $A$, the number of nuclei of both are equal. Then $\frac{N_A}{N_B}$ is

  • A
    $\frac{1}{3}$
  • B
    $\frac{1}{4}$
  • C
    $\frac{1}{6}$
  • D
    $\frac{1}{8}$

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