Heterozygous round and yellow seeded pea plan | vedclass

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(D) In a dihybrid cross involving heterozygous round and yellow seeded pea plants $(RrYy 	imes RrYy)$,the phenotypic ratio in the $F_2$ generation is

Vedclass · Accepted Answer

$150$

Vedclass · Answer

(D) In a dihybrid cross involving heterozygous round and yellow seeded pea plants $(RrYy 	imes RrYy)$,the phenotypic ratio in the $F_2$ generation is $9:3:3:1$.Here,the traits are:Round $(R)$ is dominant,Wrinkled $(r)$ is recessive.Yellow $(Y)$ is dominant,Green $(y)$ is recessive.The question asks for seeds with the first dominant trait (Round) and the second recessive trait (Green),which corresponds to the genotype $R-yy$.The probability of obtaining Round and Green seeds is $\frac{3}{16}$.Given the total number of seeds is $800$,the number of Round and Green seeds is calculated as:$800 	imes \frac{3}{16} = 50 	imes 3 = 150$.

Heterozygous round and yellow seeded pea plants were selfed and a total of $800$ seeds were collected. What is the total number of seeds with the first dominant trait (round) and the second recessive trait (green)?

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