How does the number of electric field lines d | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The number of electric field lines passing through a given surface area is defined as the electric flux $(\Phi_E)$.Mathematically, electric flux i

Vedclass · Accepted Answer

The number of field lines is directly proportional to the area.

Vedclass · Answer

(A) The number of electric field lines passing through a given surface area is defined as the electric flux $(\Phi_E)$.Mathematically, electric flux is given by the dot product of the electric field vector $(\vec{E})$ and the area vector $(\vec{A})$, expressed as $\Phi_E = \int \vec{E} \cdot d\vec{A}$.For a uniform electric field passing through a flat surface, this simplifies to $\Phi_E = EA \cos	heta$.Since the number of field lines is proportional to the electric flux, it follows that the number of field lines is directly proportional to the area $(A)$ of the surface, provided the electric field strength remains constant.

How does the number of electric field lines depend on the area?

Similar Questions

$A$ charge $Q \ C$ is placed at the center of a cube. If $\varepsilon_0$ is the permittivity of vacuum,then the flux through one face and two opposite faces of the cube is respectively:

$A$ point charge $+Q$ is positioned at the center of the base of a square pyramid as shown. The flux through one of the four identical upper faces of the pyramid is:

Three positive charges of equal value $q$ are placed at the vertices of an equilateral triangle. The resulting lines of force should be sketched as in:

You are given a dipole of charge $+q$ and $-q$ separated by a distance $2R$. $A$ sphere '$A$' of radius ' $R$ ' passes through the centre of the dipole as shown below and another sphere '$B$' of radius ' $2R$ ' passes through the charge $+q$. Then the electric flux through the sphere '$A$' is

$A$ square Gaussian surface is placed in the $y-z$ plane. Its axis is along the $x-$axis and its center is at the origin. Two identical charges,each $Q$,are placed at points $(a, 0, 0)$ and $(-a, 0, 0)$. If each side length of the square is $2a$,then the electric flux passing through the square is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module