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(D) The square is placed in the $y-z$ plane with its center at the origin $(0, 0, 0)$.The charges are located at $(a, 0, 0)$ and $(-a, 0, 0)$,which li

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zero

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(D) The square is placed in the $y-z$ plane with its center at the origin $(0, 0, 0)$.The charges are located at $(a, 0, 0)$ and $(-a, 0, 0)$,which lie on the $x-$axis.Since the square lies in the $y-z$ plane,the electric field lines produced by the charges at $(a, 0, 0)$ and $(-a, 0, 0)$ are symmetric with respect to the square.Specifically,the electric field lines from the charge at $(a, 0, 0)$ pass through the square in one direction,and the electric field lines from the charge at $(-a, 0, 0)$ pass through the square in the opposite direction.Due to the symmetry of the setup,the net electric flux passing through the square is the sum of the fluxes from both charges.Since the charges are identical and placed at equal distances from the center of the square,the flux due to one charge is equal in magnitude but opposite in sign to the flux due to the other charge.Therefore,the total electric flux passing through the square is $0$.

$A$ square Gaussian surface is placed in the $y-z$ plane. Its axis is along the $x-$axis and its center is at the origin. Two identical charges,each $Q$,are placed at points $(a, 0, 0)$ and $(-a, 0, 0)$. If each side length of the square is $2a$,then the electric flux passing through the square is:

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