How does the gravitational force (F) between | vedclass

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(D) According to the universal law of gravitation,the gravitational force $(F)$ acting between two objects is inversely proportional to the square of

Vedclass · Accepted Answer

$F'=4F$

Vedclass · Answer

(D) According to the universal law of gravitation,the gravitational force $(F)$ acting between two objects is inversely proportional to the square of the distance $(r)$ between them,i.e.,$F = G \frac{m_{1} m_{2}}{r^{2}}$If the distance $r$ is reduced to $r/2$,the new gravitational force $(F')$ will be:$F' = G \frac{m_{1} m_{2}}{(r/2)^{2}}$$F' = G \frac{m_{1} m_{2}}{r^{2}/4}$$F' = 4 	imes (G \frac{m_{1} m_{2}}{r^{2}})$$F' = 4F$Therefore,if the distance is reduced to half,the gravitational force becomes four times the original value.

How does the gravitational force $(F)$ between two objects change when the distance between them is reduced to half?

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