How many 3-digit numbers can be formed from t | vedclass

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(D) To form a $3$-digit number divisible by $5$,the digit at the units place must be $5$.Since the digits cannot be repeated,we have $1$ choice for th

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$20$

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(D) To form a $3$-digit number divisible by $5$,the digit at the units place must be $5$.Since the digits cannot be repeated,we have $1$ choice for the units place (which is $5$).For the remaining $2$ positions (tens and hundreds),we have $5$ remaining digits available $(2, 3, 6, 7, 9)$.The number of ways to fill the hundreds place is $5$.The number of ways to fill the tens place is $4$.Total number of $3$-digit numbers $= 5 	imes 4 	imes 1 = 20$.

How many $3$-digit numbers can be formed from the digits $2, 3, 5, 6, 7,$ and $9$ which are divisible by $5$,given that no digit is repeated?

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