How many 5-digit even numbers can be formed u | vedclass

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(C) To form a $5$-digit even number,the unit's place must be occupied by an even digit. The available even digits are $2$ and $4$.Case $1$: If the uni

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$24$

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(C) To form a $5$-digit even number,the unit's place must be occupied by an even digit. The available even digits are $2$ and $4$.Case $1$: If the unit's place is $2$,the remaining digits are $1, 5, 5, 4$. The number of ways to arrange these $4$ digits is $\frac{4!}{2!} = \frac{24}{2} = 12$.Case $2$: If the unit's place is $4$,the remaining digits are $1, 2, 5, 5$. The number of ways to arrange these $4$ digits is $\frac{4!}{2!} = \frac{24}{2} = 12$.Total number of $5$-digit even numbers $= 12 + 12 = 24$.

How many $5$-digit even numbers can be formed using the digits $1, 2, 5, 5, 4$?

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