How many 6 mu F, 200 V capacitors are needed | vedclass

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(D) To achieve a potential difference of $600 \ V$ using capacitors rated at $200 \ V$ each,we must connect $n$ capacitors in series such that $n 	im

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$27$

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(D) To achieve a potential difference of $600 \ V$ using capacitors rated at $200 \ V$ each,we must connect $n$ capacitors in series such that $n 	imes 200 \ V = 600 \ V$. Thus,$n = 3$. The equivalent capacitance of these $3$ capacitors in series is given by $\frac{1}{C_s} = \frac{1}{6} + \frac{1}{6} + \frac{1}{6} = \frac{3}{6} = \frac{1}{2}$,so $C_s = 2 \ \mu F$. To achieve a total capacitance of $18 \ \mu F$,we need to connect $m$ such series branches in parallel,where $m 	imes C_s = 18 \ \mu F$. Thus,$m 	imes 2 \ \mu F = 18 \ \mu F$,which gives $m = 9$. The total number of capacitors required is $n 	imes m = 3 	imes 9 = 27$.

How many $6 \mu F, 200 \ V$ capacitors are needed to make a capacitor of $18 \mu F, 600 \ V$?

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