(A) Every number between $100$ and $1000$ is a $3$-digit number. To form a $3$-digit number,the hundreds place cannot be $0$. The hundreds place can b

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(A) Every number between $100$ and $1000$ is a $3$-digit number. To form a $3$-digit number,the hundreds place cannot be $0$. The hundreds place can be filled by any of the $5$ digits $(1, 2, 3, 4, 5)$,so there are $5$ choices. The tens place can be filled by any of the remaining $5$ digits (including $0$),so there are $5$ choices. The units place can be filled by any of the remaining $4$ digits,so there are $4$ choices. Therefore,the total number of such $3$-digit numbers is $5 \times 5 \times 4 = 100$.

Class 11 Mathematics Permutations and Combinations Definition of permutation, Number of permutations with or without repetition, Conditional permutations

Easy

How many numbers lying between $100$ and $1000$ can be formed with the digits $0, 1, 2, 3, 4, 5$,if the repetition of the digits is not allowed?

A
$100$
B
$120$
C
$80$
D
$140$

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Permutations and Combinations

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Definition of permutation, Number of permutations with or without repetition, Conditional permutations

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How many numbers lying between $100$ and $1000$ can be formed with the digits $0, 1, 2, 3, 4, 5$,if the repetition of the digits is not allowed?

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How many words,with or without meaning,can be formed using the letters of the word $MONDAY$,assuming that no letter is repeated,if $4$ letters are used at a time?

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