How many pairs of letters are there in the wo | vedclass

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(A) To find the pairs,we check the sequence of letters in the word $NECESSARY$ against the English alphabet:$1$. $N$ (14th) to $S$ (19th): There are $

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(A) To find the pairs,we check the sequence of letters in the word $NECESSARY$ against the English alphabet:$1$. $N$ (14th) to $S$ (19th): There are $4$ letters between them in the word $(E, C, E, S)$ and $4$ letters in the alphabet $(O, P, Q, R)$. This is one pair.$2$. $E$ (5th) to $S$ (19th): No match.$3$. $A$ (1st) to $Y$ (25th): No match.Checking all combinations,only the pair $(N, S)$ satisfies the condition.Thus,there is only $1$ such pair.

How many pairs of letters are there in the word $NECESSARY$ which have as many letters between them in the word as there are between them in the alphabet and in the same order?

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