How many words can be made from the letters o | vedclass

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(C) The word $BHARAT$ contains $6$ letters,where $A$ repeats $2$ times.Total number of arrangements $ = \frac{6!}{2!} = \frac{720}{2} = 360$.To find t

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$240$

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(C) The word $BHARAT$ contains $6$ letters,where $A$ repeats $2$ times.Total number of arrangements $ = \frac{6!}{2!} = \frac{720}{2} = 360$.To find the number of words where $B$ and $H$ come together,we treat $(BH)$ as a single unit. Now we have $5$ units: $(BH), A, R, A, T$.The number of arrangements of these $5$ units is $\frac{5!}{2!} = 60$.Since $B$ and $H$ can be arranged within their unit in $2! = 2$ ways,the total number of words where $B$ and $H$ are together is $60 	imes 2 = 120$.The number of words where $B$ and $H$ never come together is the total number of words minus the number of words where they are together: $360 - 120 = 240$.

How many words can be made from the letters of the word $BHARAT$ in which $B$ and $H$ never come together?

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