How will you convert benzene into:
$(i)$ $p-$nitrobromobenzene
(ii) $m-$nitrochlorobenzene

(N/A) $(i)$ Conversion of benzene to $p-$nitrobromobenzene:
First,benzene undergoes bromination with $Br_2$ in the presence of anhydrous $FeBr_3$ to form bromobenzene.
Then,bromobenzene undergoes nitration with concentrated $HNO_3$ and concentrated $H_2SO_4$ to form a mixture of $o-$ and $p-$nitrobromobenzene.
The $p-$isomer is separated from the $o-$isomer by fractional distillation.
(ii) Conversion of benzene to $m-$nitrochlorobenzene:
First,benzene undergoes nitration with concentrated $HNO_3$ and concentrated $H_2SO_4$ to form nitrobenzene.
Since the nitro group $(-NO_2)$ is meta-directing,subsequent chlorination with $Cl_2$ in the presence of anhydrous $AlCl_3$ yields $m-$nitrochlorobenzene.