How will you convert butan-2-one to propanoic | vedclass

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Question

(C) Butan$-2-$one $(CH_3-CO-CH_2-CH_3)$ is a methyl ketone. It undergoes the haloform reaction when treated with $I_2$ and $NaOH$ to form a sodium sal

Vedclass · Accepted Answer

$NaOH/I_2/H^{+}$

Vedclass · Answer

(C) Butan$-2-$one $(CH_3-CO-CH_2-CH_3)$ is a methyl ketone. It undergoes the haloform reaction when treated with $I_2$ and $NaOH$ to form a sodium salt of a carboxylic acid with one less carbon atom and iodoform $(CHI_3)$. Subsequent acidification with $H^{+}$ yields propanoic acid $(CH_3-CH_2-COOH)$. $CH_3-CO-CH_2-CH_3 \xrightarrow{I_2/NaOH} CH_3-CH_2-COONa + CHI_3$ $CH_3-CH_2-COONa \xrightarrow{H^{+}} CH_3-CH_2-COOH$

How will you convert butan$-2-$one to propanoic acid?

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