How will you convert:
$(i)$ Benzene into aniline
$(ii)$ Benzene into $N,N$-dimethylaniline
$(iii)$ $Cl-(CH_2)_4-Cl$ into hexane-$1,6$-diamine?
$(i)$ Benzene into aniline
$(ii)$ Benzene into $N,N$-dimethylaniline
$(iii)$ $Cl-(CH_2)_4-Cl$ into hexane-$1,6$-diamine?
(N/A) $(i)$ Benzene $\xrightarrow{Conc. HNO_3 / Conc. H_2SO_4}$ Nitrobenzene $\xrightarrow{H_2/Pd, Ethanol}$ Aniline.
$(ii)$ Benzene $\xrightarrow{Conc. HNO_3 / Conc. H_2SO_4}$ Nitrobenzene $\xrightarrow{H_2/Pd, Ethanol}$ Aniline $\xrightarrow{2CH_3Cl}$ $N,N$-Dimethylaniline.
$(iii)$ $Cl-(CH_2)_4-Cl$ $\xrightarrow{Ethanolic NaCN}$ $NC-(CH_2)_4-CN$ $\xrightarrow{H_2/Ni}$ $H_2N-(CH_2)_6-NH_2$ (Hexane-$1,6$-diamine).
$(ii)$ Benzene $\xrightarrow{Conc. HNO_3 / Conc. H_2SO_4}$ Nitrobenzene $\xrightarrow{H_2/Pd, Ethanol}$ Aniline $\xrightarrow{2CH_3Cl}$ $N,N$-Dimethylaniline.
$(iii)$ $Cl-(CH_2)_4-Cl$ $\xrightarrow{Ethanolic NaCN}$ $NC-(CH_2)_4-CN$ $\xrightarrow{H_2/Ni}$ $H_2N-(CH_2)_6-NH_2$ (Hexane-$1,6$-diamine).
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