The product (A) of the given reaction is: | vedclass

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(A) The reaction involves the nucleophilic substitution of aniline with $1$-bromo-$4$-chlorobutane. First,the lone pair on the nitrogen atom of anilin

Vedclass · Accepted Answer

$1,2,3,4-$tetrahydroquinoline

Vedclass · Answer

(A) The reaction involves the nucleophilic substitution of aniline with $1$-bromo-$4$-chlorobutane. First,the lone pair on the nitrogen atom of aniline attacks the carbon atom attached to the bromine atom,displacing the bromide ion to form $N$-($4$-chlorobutyl)aniline. Subsequently,an intramolecular Friedel-Crafts alkylation occurs. The nitrogen atom directs the alkyl chain to the ortho position of the benzene ring. The lone pair on the nitrogen facilitates the formation of a cyclic intermediate,which then undergoes cyclization to form $1,2,3,4$-tetrahydroquinoline. Thus,the correct product $(A)$ is $1,2,3,4$-tetrahydroquinoline.

The product $(A)$ of the given reaction is:

Similar Questions

$(i)$ Write structures of different isomeric amines corresponding to the molecular formula,$C_{4}H_{11}N$. $(ii)$ Write $IUPAC$ names of all the isomers. $(iii)$ What type of isomerism is exhibited by different pairs of amines?

From $6.55 \ g$ of aniline,the maximum amount of acetanilide that can be prepared will be _ $\times 10^{-1} \ g$.

What are $X$ and $Y$ respectively in the following set of reactions?

Consider the above sequence of reactions. The number of bromine atom$(s)$ in the final product $(P)$ will be:

The product $(A)$ is:

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