Determine the hybridization of the C_3 and C_ | vedclass

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(A) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has the highest priority,so the carbon of the $-COOH$ group is $

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$sp^2, sp^2$

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(A) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has the highest priority,so the carbon of the $-COOH$ group is $C_1$.$2$. Number the chain: $C_1$ (carboxyl carbon),$C_2$ (alpha carbon),$C_3$ (carbon with double bond),$C_4$ (carbon with double bond),$C_5$ (chiral center),$C_6$ (carbon with double bond).$3$. Analyze $C_3$: The $C_3$ atom is part of a carbon-carbon double bond $(C=C)$,meaning it is bonded to three atoms (one $C$,one $C$,one $H$). Thus,its hybridization is $sp^2$.$4$. Analyze $C_6$: The $C_6$ atom is part of a terminal carbon-carbon double bond $(CH=CH_2)$,meaning it is bonded to three atoms (one $C$,two $H$). Thus,its hybridization is $sp^2$.$5$. Conclusion: Both $C_3$ and $C_6$ are $sp^2$ hybridized.

Determine the hybridization of the $C_3$ and $C_6$ carbon atoms in the given structure,respectively. (Numbering starts from the left end of the longest chain containing the principal functional group).

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