Hydrochloric acid solutions $A$ and $B$ have concentrations of $0.5 \,N$ and $0.1 \,N$ respectively. The volumes of solutions $A$ and $B$ required to make $2 \,L$ of $0.2 \,N$ hydrochloric acid are:
- A$0.5 \,L$ of $A + 1.5 \,L$ of $B$
- B$1.5 \,L$ of $A + 0.5 \,L$ of $B$
- C$1.0 \,L$ of $A + 1.0 \,L$ of $B$
- D$0.75 \,L$ of $A + 1.25 \,L$ of $B$
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