Identify A in the following reaction: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of styrene with $HBr$ in the presence of peroxide $(R_2O_2)$ proceeds via a free radical mechanism,which follows anti-Markovnikov add

Vedclass · Accepted Answer

$1-$bromo$-2-$phenylethane

Vedclass · Answer

(C) The reaction of styrene with $HBr$ in the presence of peroxide $(R_2O_2)$ proceeds via a free radical mechanism,which follows anti-Markovnikov addition.$1$. The peroxide undergoes homolytic cleavage to form alkoxy radicals $(RO^{\bullet})$.$2$. The alkoxy radical reacts with $HBr$ to generate a bromine radical $(Br^{\bullet})$.$3$. The bromine radical attacks the double bond of styrene to form a carbon-centered radical. There are two possibilities:- Attack at the terminal carbon leads to a more stable benzylic radical $(Ph-CH^{\bullet}-CH_2Br)$.- Attack at the internal carbon leads to a less stable secondary radical $(Ph-CH(Br)-CH_2^{\bullet})$.$4$. The more stable benzylic radical reacts with $HBr$ to form the major product,$1$-bromo-$2$-phenylethane $(Ph-CH_2-CH_2Br)$.

Identify $A$ in the following reaction:

Similar Questions

The reaction of $C_6H_5CH=CHCH_3$ with $HBr$ produces

Which of the following $S_N2$ reactions is the slowest?

Which of the following compounds will not undergo Friedel-Crafts reaction with benzene?

$CH_3-CH_2-CH(Br)-CH_3 \xrightarrow{Alc. KOH} X$ (major)
$CH_3-CH_2-CH(NMe_3^+) - CH_3 \xrightarrow{EtONa, \Delta} Y$ (major)
Product $(X)$ and $(Y)$ respectively are:

The product formed on the reaction of ethyl alcohol with bleaching powder is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module