Identify A and B in the following sequence of | vedclass

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(B) The reaction of toluene with $Cl_2$ in the presence of light $(hv)$ is a free radical substitution reaction. It proceeds as follows: $C_6H_5CH_3 +

Vedclass · Accepted Answer

$(A) = 	ext{Benzal chloride}, (B) = 	ext{Benzaldehyde}$

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(B) The reaction of toluene with $Cl_2$ in the presence of light $(hv)$ is a free radical substitution reaction. It proceeds as follows: $C_6H_5CH_3 + 2Cl_2 \xrightarrow{hv} C_6H_5CHCl_2 + 2HCl$ Here,$A$ is benzal chloride $(C_6H_5CHCl_2)$. Next,the hydrolysis of benzal chloride with water at $373 \ K$ yields benzaldehyde: $C_6H_5CHCl_2 + H_2O \xrightarrow{373 \ K} C_6H_5CHO + 2HCl$ Thus,$A$ is benzal chloride and $B$ is benzaldehyde.

Identify $A$ and $B$ in the following sequence of reaction:

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