Identify A in the following reaction.A + text | vedclass

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(B) The reaction is an electrophilic aromatic substitution,specifically a Friedel-Crafts alkylation.Chlorobenzene reacts with chloromethane in the pre

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Chlorobenzene

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(B) The reaction is an electrophilic aromatic substitution,specifically a Friedel-Crafts alkylation.Chlorobenzene reacts with chloromethane in the presence of anhydrous $AlCl_3$ to form $1-	ext{chloro}-2-	ext{methylbenzene}$ $(o-	ext{chlorotoluene})$ and $1-	ext{chloro}-4-	ext{methylbenzene}$ $(p-	ext{chlorotoluene})$.Since the product is a mixture of $1-	ext{chlorotoluene}$ (ortho-isomer) and $4-	ext{chlorotoluene}$ (para-isomer),the reactant $A$ must be $Chlorobenzene$ because the chlorine atom on the benzene ring is ortho/para-directing.

Identify $A$ in the following reaction.
$A + \text{chloromethane} \xrightarrow[AlCl_3]{\text{Anhydrous}} 1-\text{chlorotoluene} + 4-\text{chlorotoluene}$

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Identify $A$ in the following reaction.$A + \text{chloromethane} \xrightarrow[AlCl_3]{\text{Anhydrous}} 1-\text{chlorotoluene} + 4-\text{chlorotoluene}$