Identify the amine having the highest pK_{b} | vedclass

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Question

(C) The $pK_{b}$ value is inversely proportional to the basic strength of the amine. $A$ higher $pK_{b}$ value indicates a weaker base.$1$. $(CH_3)_2N

Vedclass · Accepted Answer

$C_6H_5NH_2$

Vedclass · Answer

(C) The $pK_{b}$ value is inversely proportional to the basic strength of the amine. $A$ higher $pK_{b}$ value indicates a weaker base.$1$. $(CH_3)_2NH$ is a secondary aliphatic amine,which is a strong base due to the electron-donating inductive effect of two methyl groups.$2$. $(CH_3)_3N$ is a tertiary aliphatic amine,which is also a strong base.$3$. $C_6H_5CH_2NH_2$ is a primary amine where the lone pair is not in conjugation with the benzene ring,making it more basic than aniline.$4$. $C_6H_5NH_2$ (aniline) is the weakest base among the given options because the lone pair on the nitrogen atom is involved in resonance with the benzene ring,reducing its availability for protonation.Since $C_6H_5NH_2$ is the weakest base,it has the highest $pK_{b}$ value.

Identify the amine having the highest $pK_{b}$ value.

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Identify product $A$ in the following reaction:
$C_6H_5N_2^+Cl^- \xrightarrow{C_2H_5OH} A + N_2 + CH_3CHO + HCl$

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