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(C) . In a series combination, $\frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2} + \dots$. This implies $C_{eq}$ is always smaller than the smallest i

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$A, C$ and $D$ only

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(C) . In a series combination, $\frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2} + \dots$. This implies $C_{eq}$ is always smaller than the smallest individual capacitance. Thus, $A$ is correct.$B$. When a dielectric is placed in an electric field, polarization occurs, leading to the displacement of charges (bound charges). Thus, $B$ is incorrect.$C$. The capacitance of a parallel plate capacitor is $C = \frac{\epsilon_0 A}{d}$. Increasing area $A$ or decreasing distance $d$ (thickness of dielectric) increases $C$. Thus, $C$ is correct.$D$. For a point charge $q$, the potential at distance $r$ is $V = \frac{kq}{r}$. Since $V$ is constant for a fixed $r$, spherical shells are equipotential surfaces. Thus, $D$ is correct.Therefore, statements $A, C,$ and $D$ are correct.

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