Identify the geometry of TeF_4 molecule from | vedclass

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(D) $1$. The central atom $Te$ has $6$ valence electrons. $2$. It forms $4$ bonds with $F$ atoms and has $1$ lone pair of electrons. $3$. The total nu

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See-saw

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(D) $1$. The central atom $Te$ has $6$ valence electrons. $2$. It forms $4$ bonds with $F$ atoms and has $1$ lone pair of electrons. $3$. The total number of electron pairs is $4 + 1 = 5$,which corresponds to $sp^3d$ hybridization. $4$. According to $VSEPR$ theory,a molecule with $5$ electron pairs and $1$ lone pair adopts a see-saw geometry.

Identify the geometry of $TeF_4$ molecule from the following.

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