Which of the following have the same shape? ( | vedclass

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(C) To determine the shape,we calculate the hybridization and number of lone pairs for each species: $(i)$ $ICl_2^-$: Central atom $I$ has $7$ valence

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$(i)$ and $(iv)$

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(C) To determine the shape,we calculate the hybridization and number of lone pairs for each species: $(i)$ $ICl_2^-$: Central atom $I$ has $7$ valence electrons + $2$ (from $Cl$) + $1$ (negative charge) = $10$ electrons. Hybridization is $sp^3d$ with $3$ lone pairs on the equatorial position. Shape is linear. $(ii)$ $SO_2$: Central atom $S$ has $6$ valence electrons. Hybridization is $sp^2$ with $1$ lone pair. Shape is bent ($V$-shaped). $(iii)$ $SnCl_2$: Central atom $Sn$ has $4$ valence electrons. Hybridization is $sp^2$ with $1$ lone pair. Shape is bent ($V$-shaped). $(iv)$ $XeF_2$: Central atom $Xe$ has $8$ valence electrons + $2$ (from $F$) = $10$ electrons. Hybridization is $sp^3d$ with $3$ lone pairs on the equatorial position. Shape is linear. Both $ICl_2^-$ and $XeF_2$ have a linear shape,while $SO_2$ and $SnCl_2$ have a bent shape. Therefore,$(i)$ and $(iv)$ have the same shape.

Which of the following have the same shape?
$(i)$ $ICl_2^-$
$(ii)$ $SO_2$
$(iii)$ $SnCl_2$
$(iv)$ $XeF_2$

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Which of the following have the same shape? $(i)$ $ICl_2^-$ $(ii)$ $SO_2$ $(iii)$ $SnCl_2$ $(iv)$ $XeF_2$