Identify the order in which the spin-only mag | vedclass

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(D) The spin-only magnetic moment $(\mu)$ is calculated using the formula: $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.El

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$III, II, IV, I$

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(D) The spin-only magnetic moment $(\mu)$ is calculated using the formula: $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.Electronic configurations and unpaired electrons $(n)$:$I. Fe^{2+}: [Ar] 3d^6 \rightarrow n = 4$$II. Ti^{2+}: [Ar] 3d^2 \rightarrow n = 2$$III. Cu^{2+}: [Ar] 3d^9 \rightarrow n = 1$$IV. V^{2+}: [Ar] 3d^3 \rightarrow n = 3$The magnetic moment increases with the number of unpaired electrons.Comparing $n$ values: $1 (III) Therefore,the increasing order is $III < II < IV < I$.

Identify the order in which the spin-only magnetic moment (in $BM$) increases for the following four ions:
$I. Fe^{2+}$
$II. Ti^{2+}$
$III. Cu^{2+}$
$IV. V^{2+}$

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Identify the order in which the spin-only magnetic moment (in $BM$) increases for the following four ions:$I. Fe^{2+}$$II. Ti^{2+}$$III. Cu^{2+}$$IV. V^{2+}$