Class 12Chemistry2 Aldehydes, Ketones and Carboxylic Acids: Carboxylic Acids and their DerivativesPreparation of Carboxylic Acids and Their Derivatives
MediumIdentify the product formed in the following reaction.
$C_6H_5-CH_2-CH_3 \xrightarrow[ii) H_3O^{+}]{i) \text{alk. } KMnO_4} \text{Product}$
$C_6H_5-CH_2-CH_3 \xrightarrow[ii) H_3O^{+}]{i) \text{alk. } KMnO_4} \text{Product}$
- A$C_6H_5-CH_2-COOH$
- B$C_6H_5CH_2-CH_2-COOH$
- C$C_6H_5-OH$
- D$C_6H_5-COOH$
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Similar Questions
In this reaction,product $X$ is
$CH_3-CH_2-Br$ $\xrightarrow{alc. KCN} CH_3CH_2CN$ $\xrightarrow{HOH} X$
$CH_3-CH_2-Br$ $\xrightarrow{alc. KCN} CH_3CH_2CN$ $\xrightarrow{HOH} X$
Medium
View SolutionIn the reaction $CH_3CN \xrightarrow{H_3O^+, \text{heat}} CH_3COOH$,what is the change in the hybridization state of the functional carbon atom?
Easy
View SolutionIdentify the product formed in the following reaction.
$CH_3CH_2MgBr \xrightarrow[\text{ii) dil. } HCl]{\text{i) Dry ice / dry ether}} \text{Product}$
$CH_3CH_2MgBr \xrightarrow[\text{ii) dil. } HCl]{\text{i) Dry ice / dry ether}} \text{Product}$
In a reaction,$(CH_3)_2CHMgBr + CO_2$ $\xrightarrow[\text{dry ether}]{} A$ $\xrightarrow[dil. HCl]{H_2O} B$. Find the product '$B$' of the above reaction.
Identify the product $C$ in the following reaction sequence:
$1$-bromo-$4$-chlorobenzene $+ Mg (1 \text{ mole})$ $\xrightarrow{THF} A$ $\xrightarrow{CO_2} B$ $\xrightarrow{H^+} C$
$1$-bromo-$4$-chlorobenzene $+ Mg (1 \text{ mole})$ $\xrightarrow{THF} A$ $\xrightarrow{CO_2} B$ $\xrightarrow{H^+} C$
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