If $\tan^{-1} (x^2 + 3|x|-4) = \tan^{-1} (4\pi + \sin^{-1}(\sin 14))$,then the value of $\cos^{-1}(\cos 3|x|)$ is equal to

  • A
    $3\pi - 9$
  • B
    $4\pi - 9$
  • C
    $9$
  • D
    $9 - 2\pi$

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Similar Questions

Let $Z$ denote the set of integers. Then match the items in List-$I$ with those of the items in List-$II$.
List-$I$ List-$II$
$A$. $\sin ^{-1}\left(\frac{2 \sqrt{2}}{3}\right)+\sin ^{-1} \frac{1}{3}$ $I$. $k \pi \pm(-1)^k \frac{\pi}{6}, k \in Z$
$B$. $\sin ^{-1}\left(\frac{(-1)^n}{2}\right), n \in Z$ $II$. $k \pi \pm 1, k \in Z$
$C$. $\tan ^{-1}\left(\sec \frac{\pi}{4}+\tan \frac{\pi}{4}\right)$ $III$. $\frac{3}{2}$
$D$. $\sin ^{-1}|\sin x|=\sqrt{\sin ^{-1}|\sin x|} \Rightarrow x \in$ $IV$. $\frac{3 \pi}{8}$
$V$. $\frac{\pi}{2}$

The correct match is:

$\sin ^{-1}\left(\frac{12}{13}\right)+\cos ^{-1}\left(\frac{4}{5}\right)+\tan ^{-1}\left(\frac{63}{16}\right)=$

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Identify the pair$(s)$ of functions which are identical.

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