If (p wedge sim q) wedge r to sim r is F,then | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given logical statement is $(p \wedge \sim q) \wedge r 	o \sim r = F$.An implication $A 	o B$ is false $(F)$ only when $A$ is true $(T)$ and

Vedclass · Accepted Answer

$T$

Vedclass · Answer

(A) The given logical statement is $(p \wedge \sim q) \wedge r 	o \sim r = F$.An implication $A 	o B$ is false $(F)$ only when $A$ is true $(T)$ and $B$ is false $(F)$.Therefore,$(p \wedge \sim q) \wedge r = T$ and $\sim r = F$.From $\sim r = F$,we get $r = T$.Checking the first part: if $r = T$,then $(p \wedge \sim q) \wedge T = T$,which implies $(p \wedge \sim q) = T$.This is possible if $p = T$ and $q = F$.Since the condition holds for $r = T$,the truth value of $r$ is $T$.

If $(p \wedge \sim q) \wedge r \to \sim r$ is $F$,then the truth value of $r$ is:

Similar Questions

Let $A, B, C$ and $D$ be four non-empty sets. The contrapositive statement of "If $A \subseteq B$ and $B \subseteq D,$ then $A \subseteq C$" is

Let $a: \sim(p \wedge \sim r) \vee(\sim q \vee s)$ and $b: (p \vee s) \leftrightarrow(q \wedge r)$. If the truth values of $p$ and $q$ are $T$ and that of $r$ and $s$ are $F$,then the truth values of $a$ and $b$ are respectively...

The statement pattern $p \rightarrow \sim(p \wedge \sim q)$ is equivalent to

For each of the following compound statements,first identify the connecting words and then break it into component statements.
Square of an integer is positive or negative.

The contrapositive of $\sim q \to p$ is equivalent to

Vedclass Test Series

Exam Paper Generator

Online Exam Module