If A and B are two vectors such that |A + B| | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given the condition: $|A + B| = 2|A - B|$.Squaring both sides,we get: $|A + B|^2 = 4|A - B|^2$.Using the vector identity $|u \pm v|^2 = |u|^2 + |v

Vedclass · Accepted Answer

Data insufficient

Vedclass · Answer

(D) Given the condition: $|A + B| = 2|A - B|$.Squaring both sides,we get: $|A + B|^2 = 4|A - B|^2$.Using the vector identity $|u \pm v|^2 = |u|^2 + |v|^2 \pm 2|u||v| \cos 	heta$,we have:$A^2 + B^2 + 2AB \cos 	heta = 4(A^2 + B^2 - 2AB \cos 	heta)$.$A^2 + B^2 + 2AB \cos 	heta = 4A^2 + 4B^2 - 8AB \cos 	heta$.$10AB \cos 	heta = 3A^2 + 3B^2$.$\cos 	heta = \frac{3(A^2 + B^2)}{10AB}$.Since the value of $\cos 	heta$ depends on the magnitudes of $A$ and $B$,and they are not provided,the angle $	heta$ cannot be uniquely determined. Thus,the data is insufficient.

Column $-I$	Column $-II$
$(1)$ Angular momentum	$(a)$ Scalar
$(2)$ Potential energy	$(b)$ Vector
	$(c)$ Unit vector

If $A$ and $B$ are two vectors such that $|A + B| = 2|A - B|$,the angle between vectors $A$ and $B$ is:

Similar Questions

Find the angle between $\vec{A} = 3\hat{i} - \hat{j} + 4\hat{k}$ and the $Z$-axis.

Match Column $-I$ with Column $-II$.

Column $-I$ Column $-II$

$(1)$ Angular momentum $(a)$ Scalar

$(2)$ Potential energy $(b)$ Vector

$(c)$ Unit vector

If $|\vec{P}+\vec{Q}|=|\vec{P}|=|\vec{Q}|$,then the angle between $\vec{P}$ and $\vec{Q}$ is: (in $^{\circ}$)

If $A = 3\hat i + 4\hat j$ and $B = 7\hat i + 24\hat j,$ the vector having the same magnitude as $B$ and parallel to $A$ is

There are two vectors $\vec{A} = 6\hat{i} + 9\hat{j} - \hat{k}$ and $\vec{B} = 2\hat{i} + 3\hat{j} - p\hat{k}$ which have the same direction. The value of '$p$' is

Vedclass Test Series

Exam Paper Generator

Online Exam Module