If I = 50, kg-m^2,then how much torque (in N- | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given: Moment of inertia $I = 50\, kg-m^2$,initial angular velocity $\omega_i = 20\, rad/s$,final angular velocity $\omega_f = 0\, rad/s$,and time

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(A) Given: Moment of inertia $I = 50\, kg-m^2$,initial angular velocity $\omega_i = 20\, rad/s$,final angular velocity $\omega_f = 0\, rad/s$,and time $t = 10\, s$.Angular acceleration $\alpha = \frac{\omega_f - \omega_i}{t} = \frac{0 - 20}{10} = -2\, rad/s^2$.The torque required is given by $	au = I \alpha$.$	au = 50 	imes (-2) = -100\, N-m$.The magnitude of the torque applied is $100\, N-m$ in the direction opposite to the angular velocity.

If $I = 50\, kg-m^2$,then how much torque (in $N-m$) will be applied to stop it in $10\, s$? Its initial angular speed is $20\, rad/s$.

Similar Questions

An object $1\;cm$ tall is placed $4\;cm$ in front of a mirror. In order to produce an upright image of $3\;cm$ height,one needs a:

Selection is a method related to which of the following?

The percentage composition of an organic compound $A$ is: carbon $85.71 \%$ and hydrogen $14.29 \%$. Its vapour density is $14$. Consider the following reaction sequence:
$A$ $\xrightarrow{Cl_2 / H_2O} B$ $\xrightarrow[(ii) H_3O^+]{(i) KCN / EtOH} C$
Identify $\underline{C}$.

Which of the following could act as a propellant for rockets?

If $\alpha, \beta, \gamma$ are the roots of the equation $x^3+4x+1=0$,then $(\alpha+\beta)^{-1}+(\beta+\gamma)^{-1}+(\gamma+\alpha)^{-1}$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module