If Z_{eff} of boron is x,then Z_{eff} of oxyg | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The atomic number of Boron is $5$. The electronic configuration is $1s^2 2s^2 2p^1$.Using Slater's rules,the shielding constant $\sigma$ for the $

Vedclass · Accepted Answer

$x + 1.95$

Vedclass · Answer

(D) The atomic number of Boron is $5$. The electronic configuration is $1s^2 2s^2 2p^1$.Using Slater's rules,the shielding constant $\sigma$ for the $2p$ electron is $(2 	imes 0.85) + (2 	imes 0.35) = 1.7 + 0.7 = 2.4$.Thus,$Z_{eff} = Z - \sigma = 5 - 2.4 = 2.6$. Let this be $x$.The atomic number of Oxygen is $8$. The electronic configuration is $1s^2 2s^2 2p^4$.Using Slater's rules,the shielding constant $\sigma$ for a $2p$ electron is $(2 	imes 0.85) + (5 	imes 0.35) = 1.7 + 1.75 = 3.45$.Thus,$Z_{eff} = 8 - 3.45 = 4.55$.Comparing the two values: $4.55 - 2.6 = 1.95$.Therefore,the $Z_{eff}$ of oxygen is $x + 1.95$.

If $Z_{eff}$ of boron is $x$,then $Z_{eff}$ of oxygen will be

Similar Questions

The screening effect of inner electrons of the nucleus causes

The value of the screening constant for an electron in a $3s$ orbital is identical to that of an electron present in which of the following orbitals?

In which pair does the first element have a higher $Z_{eff}$ than the second atom?

The unpaired electrons in $Al$ and $Si$ are present in the $3p$ orbital. Which electrons will experience a higher effective nuclear charge from the nucleus?

Which of the following statements is most appropriate for the effective nuclear charge? On what does it depend?

Vedclass Test Series

Exam Paper Generator

Online Exam Module