If F_1 and F_2 are two vectors of equal magni | vedclass

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(A) Given that $|F_1| = |F_2| = F$ and $|F_1 \cdot F_2| = |F_1 	imes F_2|$.Using the definitions of dot and cross products: $F^2 \cos 	heta = F^2 \s

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$\sqrt{2+\sqrt{2}} F$

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(A) Given that $|F_1| = |F_2| = F$ and $|F_1 \cdot F_2| = |F_1 	imes F_2|$.Using the definitions of dot and cross products: $F^2 \cos 	heta = F^2 \sin 	heta$.This implies $	an 	heta = 1$,so $	heta = 45^{\circ}$.The magnitude of the resultant vector is given by $|F_1 + F_2| = \sqrt{F_1^2 + F_2^2 + 2F_1F_2 \cos 	heta}$.Substituting the values: $|F_1 + F_2| = \sqrt{F^2 + F^2 + 2F^2 \cos 45^{\circ}}$.$|F_1 + F_2| = \sqrt{2F^2 + 2F^2 \left(\frac{1}{\sqrt{2}}ight)} = \sqrt{2F^2 + F^2 \sqrt{2}}$.$|F_1 + F_2| = F \sqrt{2 + \sqrt{2}}$.

If $F_1$ and $F_2$ are two vectors of equal magnitudes $F$ such that $|F_1 \cdot F_2| = |F_1 \times F_2|$,then $|F_1 + F_2|$ is equal to

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