If V_m is the velocity of sound in moist air | vedclass

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(A) The velocity of sound in a gas is given by the formula $V = \sqrt{\frac{\gamma P}{\rho}}$,where $\gamma$ is the adiabatic index,$P$ is the pressur

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$V_m > V_d$

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(A) The velocity of sound in a gas is given by the formula $V = \sqrt{\frac{\gamma P}{\rho}}$,where $\gamma$ is the adiabatic index,$P$ is the pressure,and $\rho$ is the density of the gas.Under identical conditions of pressure and temperature,the velocity of sound is inversely proportional to the square root of the density of the medium: $V \propto \frac{1}{\sqrt{\rho}}$.Moist air contains water vapor,which has a lower molecular mass compared to the nitrogen and oxygen molecules that make up dry air. Therefore,the density of moist air is less than the density of dry air $(\rho_m Since the density of moist air is lower,the velocity of sound in moist air must be greater than the velocity of sound in dry air $(V_m > V_d)$.

If $V_m$ is the velocity of sound in moist air and $V_d$ is the velocity of sound in dry air,under identical conditions of pressure and temperature,which of the following is true?

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