यदि $A=\left[\begin{array}{ccc}2 & -1 & 1 \\ -1 & 2 & -1 \\ 1 & -1 & 2\end{array}\right]$ है,तो सत्यापित कीजिए कि $A^{3}-6 A^{2}+9 A-4 I=0$ और इसके प्रयोग से $A^{-1}$ ज्ञात कीजिए।

  • A
    $\frac{1}{4}\left[\begin{array}{ccc}3 & 1 & -1 \\ 1 & 3 & 1 \\ -1 & 1 & 3\end{array}\right]$
  • B
    $\frac{1}{4}\left[\begin{array}{ccc}1 & 3 & 1 \\ 3 & 1 & -1 \\ 1 & -1 & 3\end{array}\right]$
  • C
    $\frac{1}{4}\left[\begin{array}{ccc}3 & -1 & 1 \\ -1 & 3 & 1 \\ 1 & 1 & 3\end{array}\right]$
  • D
    $\frac{1}{4}\left[\begin{array}{ccc}1 & 1 & 1 \\ 1 & 1 & 1 \\ 1 & 1 & 1\end{array}\right]$

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यदि $A = \begin{bmatrix} 2 & -3 \\ -4 & 1 \end{bmatrix}$ है,तो $\text{adj}(3A^2 + 12A) = \dots$

आव्यूह $A = \begin{bmatrix} 2 & -3 \\ 3 & 5 \end{bmatrix}$ का सहखंडज (adjoint) ज्ञात कीजिए।

यदि $A$ एक नॉन-सिंगुलर आव्यूह है ताकि $A \cdot A^T = A^T \cdot A$ और $B = A^{-1} \cdot A^T$ हो,तो

यदि $A = \begin{bmatrix} 5a & -b \\ 3 & 2 \end{bmatrix}$ और $A \cdot \text{adj}(A) = AA^T$ है,तो $5a + b =$ ज्ञात कीजिए।

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