If A = { x : x text{ is a natural number} },B | vedclass

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(A) Given sets are:$A = \{ 1, 2, 3, 4, 5, \ldots \}$$B = \{ 2, 4, 6, 8, \ldots \}$$C = \{ 1, 3, 5, 7, 9, \ldots \}$$D = \{ 2, 3, 5, 7, \ldots \}$The i

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$B$

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(A) Given sets are:$A = \{ 1, 2, 3, 4, 5, \ldots \}$$B = \{ 2, 4, 6, 8, \ldots \}$$C = \{ 1, 3, 5, 7, 9, \ldots \}$$D = \{ 2, 3, 5, 7, \ldots \}$The intersection $A \cap B$ consists of elements that are common to both set $A$ and set $B$.Since $B$ is a subset of $A$ $(B \subset A)$,the intersection of $A$ and $B$ is $B$ itself.$A \cap B = \{ x : x \in A 	ext{ and } x \in B \} = \{ x : x 	ext{ is an even natural number} \} = B$.

If $A = \{ x : x \text{ is a natural number} \}$,$B = \{ x : x \text{ is an even natural number} \}$,$C = \{ x : x \text{ is an odd natural number} \}$,and $D = \{ x : x \text{ is a prime number} \}$,find $A \cap B$.

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