Difficult
If $1 \ g$ of each of the following gases are taken at $STP$,which of the gases will occupy $(a)$ greatest volume and $(b)$ smallest volume? $CO, H_2O, CH_4, NO$
(N/A) From Avogadro's law,the volume of $1 \ mol$ of any gas at $STP$ is $22.4 \ L$.
The volume occupied by $1 \ g$ of a gas is given by $\frac{22.4 \ L}{\text{Molar mass in } g \ mol^{-1}}$.
$1$. For $CO$ (Molar mass $= 28 \ g \ mol^{-1}$): Volume $= \frac{22.4}{28} = 0.80 \ L$.
$2$. For $H_2O$ (Molar mass $= 18 \ g \ mol^{-1}$): Volume $= \frac{22.4}{18} \approx 1.24 \ L$.
$3$. For $CH_4$ (Molar mass $= 16 \ g \ mol^{-1}$): Volume $= \frac{22.4}{16} = 1.40 \ L$.
$4$. For $NO$ (Molar mass $= 30 \ g \ mol^{-1}$): Volume $= \frac{22.4}{30} \approx 0.75 \ L$.
Comparing the volumes,$CH_4$ occupies the greatest volume $(1.40 \ L)$ and $NO$ occupies the smallest volume $(0.75 \ L)$.
The volume occupied by $1 \ g$ of a gas is given by $\frac{22.4 \ L}{\text{Molar mass in } g \ mol^{-1}}$.
$1$. For $CO$ (Molar mass $= 28 \ g \ mol^{-1}$): Volume $= \frac{22.4}{28} = 0.80 \ L$.
$2$. For $H_2O$ (Molar mass $= 18 \ g \ mol^{-1}$): Volume $= \frac{22.4}{18} \approx 1.24 \ L$.
$3$. For $CH_4$ (Molar mass $= 16 \ g \ mol^{-1}$): Volume $= \frac{22.4}{16} = 1.40 \ L$.
$4$. For $NO$ (Molar mass $= 30 \ g \ mol^{-1}$): Volume $= \frac{22.4}{30} \approx 0.75 \ L$.
Comparing the volumes,$CH_4$ occupies the greatest volume $(1.40 \ L)$ and $NO$ occupies the smallest volume $(0.75 \ L)$.
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Column - $A$ Column - $B$ $(A)$ $88 \ g$ of $CO_2$ $(1)$ $0.2 \ mol$ $(B)$ $6.022 \times 10^{23}$ molecules of water $(2)$ $2 \ mol$ $(C)$ $5.6 \ L$ of $O_2$ at $STP$ $(3)$ $1 \ mol$ $(D)$ $96 \ g$ of $O_2$ $(4)$ $6.022 \times 10^{23}$ molecules $(E)$ One mole of any gas at $STP$ $(5)$ $3 \ mol$
| Column - $A$ | Column - $B$ |
| $(A)$ $88 \ g$ of $CO_2$ | $(1)$ $0.2 \ mol$ |
| $(B)$ $6.022 \times 10^{23}$ molecules of water | $(2)$ $2 \ mol$ |
| $(C)$ $5.6 \ L$ of $O_2$ at $STP$ | $(3)$ $1 \ mol$ |
| $(D)$ $96 \ g$ of $O_2$ | $(4)$ $6.022 \times 10^{23}$ molecules |
| $(E)$ One mole of any gas at $STP$ | $(5)$ $3 \ mol$ |
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