If |x-2| geq |x-4| then x in ldots | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given the inequality $|x-2| \geq |x-4|$.Since both sides are non-negative,we can square both sides:$(x-2)^2 \geq (x-4)^2$$x^2 - 4x + 4 \geq x^2 -

Vedclass · Accepted Answer

$[3, \infty)$

Vedclass · Answer

(B) Given the inequality $|x-2| \geq |x-4|$.Since both sides are non-negative,we can square both sides:$(x-2)^2 \geq (x-4)^2$$x^2 - 4x + 4 \geq x^2 - 8x + 16$Subtract $x^2$ from both sides:$-4x + 4 \geq -8x + 16$Add $8x$ to both sides:$4x + 4 \geq 16$Subtract $4$ from both sides:$4x \geq 12$Divide by $4$:$x \geq 3$Thus,$x \in [3, \infty)$.

If $|x-2| \geq |x-4|$ then $x \in \ldots$

Similar Questions

Solve the inequality for real $x$: $3(2x - 1) + 5 \leq \frac{1}{2}(x + 15)$

Solve $3x - 22 \geq 5$ for $x \in R$.

If $\frac{x^{2}}{x-5} < 0$,then $x \in$

Solve the inequality $-6x \leq 18$ for the following cases:
$(1)$ $x \in N$
$(2)$ $x \in Z$
$(3)$ $x \in R$

Solve $30x < 200$ when $x$ is an integer.

Vedclass Test Series

Exam Paper Generator

Online Exam Module