If (x+y):(x-y)=11:1,find the value of frac{(5 | vedclass

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(C) Given the ratio: $\frac{x+y}{x-y} = \frac{11}{1}$.Cross-multiplying,we get: $x+y = 11(x-y)$.Expanding the equation: $x+y = 11x - 11y$.Rearranging

Vedclass · Accepted Answer

$\frac{-45}{4}$

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(C) Given the ratio: $\frac{x+y}{x-y} = \frac{11}{1}$.Cross-multiplying,we get: $x+y = 11(x-y)$.Expanding the equation: $x+y = 11x - 11y$.Rearranging the terms to solve for $x$ in terms of $y$: $11y + y = 11x - x$,which simplifies to $12y = 10x$.Dividing by $2$,we get $6y = 5x$,or $x = \frac{6y}{5}$.Now,substitute $x = \frac{6y}{5}$ into the expression $\frac{5x+3y}{x-2y}$:Numerator: $5(\frac{6y}{5}) + 3y = 6y + 3y = 9y$.Denominator: $\frac{6y}{5} - 2y = \frac{6y - 10y}{5} = \frac{-4y}{5}$.Therefore,the value is $\frac{9y}{-4y/5} = 9y 	imes (\frac{-5}{4y}) = \frac{-45}{4}$.

If $(x+y):(x-y)=11:1$,find the value of $\frac{(5x+3y)}{(x-2y)}$.

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