If a-b : b-c : c-d = 1 : 2 : 3,then what is t | vedclass

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(B) Given the ratio $a-b : b-c : c-d = 1 : 2 : 3$.Let $a-b = k$,$b-c = 2k$,and $c-d = 3k$ for some constant $k$.Adding these equations:$(a-b) + (b-c)

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$2 : 1$

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(B) Given the ratio $a-b : b-c : c-d = 1 : 2 : 3$.Let $a-b = k$,$b-c = 2k$,and $c-d = 3k$ for some constant $k$.Adding these equations:$(a-b) + (b-c) + (c-d) = k + 2k + 3k$$a - d = 6k$.Now,we need to express $a$ and $d$ in terms of $c$ and $k$ to find $(a+d) : c$.From $c-d = 3k$,we get $d = c - 3k$.From $b-c = 2k$,we get $b = c + 2k$.From $a-b = k$,we get $a = b + k = (c + 2k) + k = c + 3k$.Now calculate $a+d$:$a + d = (c + 3k) + (c - 3k) = 2c$.Therefore,the ratio $(a+d) : c = 2c : c = 2 : 1$.

If $a-b : b-c : c-d = 1 : 2 : 3$,then what is the value of $(a+d) : c$?

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