If left(x+frac{1}{x}right):left(x-frac{1}{x}r | vedclass

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(D) Given the ratio: $\frac{x + \frac{1}{x}}{x - \frac{1}{x}} = \frac{5}{5} = 1$.
Cross-multiplying gives: $x + \frac{1}{x} = x - \frac{1}{x}$.
Subt

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(D) Given the ratio: $\frac{x + \frac{1}{x}}{x - \frac{1}{x}} = \frac{5}{5} = 1$.
Cross-multiplying gives: $x + \frac{1}{x} = x - \frac{1}{x}$.
Subtracting $x$ from both sides: $\frac{1}{x} = -\frac{1}{x}$.
Adding $\frac{1}{x}$ to both sides: $\frac{2}{x} = 0$.
This implies $2 = 0$,which is a contradiction.
Therefore,there is no finite value of $x$ that satisfies the given equation. Thus,no solution exists.

If $\left(x+\frac{1}{x}\right):\left(x-\frac{1}{x}\right)=5:5$,then the value$(s)$ of $x$ is/are:

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