If sqrt{2} = 1.414,the square root of frac{sq | vedclass

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(B) To find the square root of $\frac{\sqrt{2}-1}{\sqrt{2}+1}$,we first rationalize the denominator:$\frac{\sqrt{2}-1}{\sqrt{2}+1} = \frac{(\sqrt{2}-1

Vedclass · Accepted Answer

$0.414$

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(B) To find the square root of $\frac{\sqrt{2}-1}{\sqrt{2}+1}$,we first rationalize the denominator:$\frac{\sqrt{2}-1}{\sqrt{2}+1} = \frac{(\sqrt{2}-1)(\sqrt{2}-1)}{(\sqrt{2}+1)(\sqrt{2}-1)} = \frac{(\sqrt{2}-1)^2}{2-1} = (\sqrt{2}-1)^2$.Now,we need to find the square root of this expression:$\sqrt{(\sqrt{2}-1)^2} = \sqrt{2}-1$.Given $\sqrt{2} = 1.414$,we substitute this value:$1.414 - 1 = 0.414$.

If $\sqrt{2} = 1.414$,the square root of $\frac{\sqrt{2}-1}{\sqrt{2}+1}$ is nearest to

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