If a = 0.1039, then the value of sqrt{4a^{2} | vedclass

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(C) The given expression is $\sqrt{4a^{2} - 4a + 1} + 3a$.First,simplify the term inside the square root: $4a^{2} - 4a + 1 = (2a - 1)^{2}$.Thus,the ex

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$1.1039$

Vedclass · Answer

(C) The given expression is $\sqrt{4a^{2} - 4a + 1} + 3a$.First,simplify the term inside the square root: $4a^{2} - 4a + 1 = (2a - 1)^{2}$.Thus,the expression becomes $\sqrt{(2a - 1)^{2}} + 3a = |2a - 1| + 3a$.Since $a = 0.1039$,$2a = 0.2078$,which is less than $1$. Therefore,$|2a - 1| = -(2a - 1) = 1 - 2a$.Substituting this back into the expression: $(1 - 2a) + 3a = a + 1$.Now,substitute the value of $a$: $0.1039 + 1 = 1.1039$.

If $a = 0.1039,$ then the value of $\sqrt{4a^{2} - 4a + 1} + 3a$ is

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