If sqrt{1+frac{x}{961}}=frac{32}{31}, then th | vedclass

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Question

(A) Given the equation: $\sqrt{1+\frac{x}{961}}=\frac{32}{31}$Squaring both sides of the equation,we get:$1+\frac{x}{961} = \left(\frac{32}{31}\right)

Vedclass · Accepted Answer

$63$

Vedclass · Answer

(A) Given the equation: $\sqrt{1+\frac{x}{961}}=\frac{32}{31}$Squaring both sides of the equation,we get:$1+\frac{x}{961} = \left(\frac{32}{31}\right)^2$Calculate the square of the fraction:$1+\frac{x}{961} = \frac{1024}{961}$Subtract $1$ from both sides:$\frac{x}{961} = \frac{1024}{961} - 1$Simplify the right side by finding a common denominator:$\frac{x}{961} = \frac{1024 - 961}{961}$$\frac{x}{961} = \frac{63}{961}$Multiplying both sides by $961$,we get:$x = 63$

If $\sqrt{1+\frac{x}{961}}=\frac{32}{31},$ then the value of $x$ is

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