When HCl is added to 2-methylpropene, what is | vedclass

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(C) The reactant is $2$-methylpropene, which has the structure $CH_2=C(CH_3)_2$.When $HCl$ is added to an unsymmetrical alkene, the reaction follows M

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$CH_3-C(Cl)(CH_3)_2$

Vedclass · Answer

(C) The reactant is $2$-methylpropene, which has the structure $CH_2=C(CH_3)_2$.When $HCl$ is added to an unsymmetrical alkene, the reaction follows Markovnikov's rule.According to Markovnikov's rule, the electrophile $(H^+)$ adds to the carbon atom of the double bond that has a greater number of hydrogen atoms, and the nucleophile $(Cl^-)$ adds to the carbon atom with fewer hydrogen atoms.The reaction is: $CH_2=C(CH_3)_2 + HCl \rightarrow CH_3-C(Cl)(CH_3)_2$.The major product formed is $2$-chloro-$2$-methylpropane.

When $HCl$ is added to $2$-methylpropene, what is the major product formed?

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