If 3 is a root of the equation {x^2} + kx - 2 | vedclass

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Question

(C) Given that $3$ is a root of the quadratic equation ${x^2} + kx - 24 = 0.$Substituting $x = 3$ into the equation:${3^2} + k(3) - 24 = 0$$9 + 3k - 2

Vedclass · Accepted Answer

${x^2} - kx + 6 = 0$

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(C) Given that $3$ is a root of the quadratic equation ${x^2} + kx - 24 = 0.$Substituting $x = 3$ into the equation:${3^2} + k(3) - 24 = 0$$9 + 3k - 24 = 0$$3k - 15 = 0$$3k = 15$$k = 5$Now,we check which equation is satisfied by $x = 3$ when $k = 5$:For option $(c)$: ${x^2} - kx + 6 = 0$Substituting $x = 3$ and $k = 5$:${3^2} - 5(3) + 6 = 9 - 15 + 6 = 0$Since the result is $0$,$3$ is a root of the equation ${x^2} - kx + 6 = 0$.

If $3$ is a root of the equation ${x^2} + kx - 24 = 0,$ then $3$ is also a root of which of the following equations?

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